Some Basic Concepts Of Chemistry Question 79
Question: 10 moles $ SO _2 $ and 15 moles $ O _2 $ were allowed to react over a suitable catalyst. 8 moles of $ SO _3 $ were formed. The remaining moles of $ SO _2 $ and $ O _2 $ respectively are-
Options:
A) 2 moles, 11 moles
B) 2 moles, 8 moles
C) 4 moles, 5 moles
D) 8 moles, 2 moles
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \underset{10}{\mathop{2SO _2}},+\underset{15}{\mathop{O _2}},\xrightarrow{{}}\underset{0}{\mathop{2SO _3}}, $
$ 10-2x~~~~~~~15-x~~~~~2x $
$ \therefore 2x=8,c=4 $ Hence, remaining, $ SO _2=10-8=2 $ moles, $ O _2=15-4=11 $ moles
