Some Basic Concepts Of Chemistry Question 64
Question: 1.12 mL of a gas is produced at S.T.P. by the action of 4.12 mg of alcohol ROH with methyl magnesium Iodide. The molecular mass of alcohol is
Options:
A) 16.0
B) 41.2
C) 82.4
D) 156.0
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Let the alcohol be ROH and x its molecular weight $ \underset{xg}{\mathop{ROH}},+CH _3MgI\to \underset{16g}{\mathop{CH _4}},+ROMgI $
$ \frac{4.12}{1000}g $ of alcohol will produce $ \frac{16}{x}\times \frac{4.12}{1000}g $ of methane Methane actually obtained is = $ \frac{16\times 1.12}{22400}g $
$ \therefore \frac{16\times 4.12}{x\times 1000}=\frac{16\times 1.12}{22400}=x=82.4 $
