SATHEE: Some Basic Concepts Of Chemistry Question 64

Some Basic Concepts Of Chemistry Question 64

Question: 1.12 mL of a gas is produced at S.T.P. by the action of 4.12 mg of alcohol ROH with methyl magnesium Iodide. The molecular mass of alcohol is

Options:

A) 16.0

B) 41.2

C) 82.4

D) 156.0

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Let the alcohol be ROH and x its molecular weight $\underset{x g}{R O H}, + C H_{3} M g I \to \underset{16 g}{C H_{4}}, + R O M g I$

$\frac{4.12}{1000} g$ of alcohol will produce $\frac{16}{x} \times \frac{4.12}{1000} g$ of methane Methane actually obtained is = $\frac{16 \times 1.12}{22400} g$

$∴ \frac{16 \times 4.12}{x \times 1000} = \frac{16 \times 1.12}{22400} = x = 82.4$

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Some Basic Concepts Of Chemistry Question 64

Question: 1.12 mL of a gas is produced at S.T.P. by the action of 4.12 mg of alcohol ROH with methyl magnesium Iodide. The molecular mass of alcohol is

Options:

Answer:

Solution:

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