Some Basic Concepts Of Chemistry Question 6

Question: The mass of 70% $ H _2SO _4 $ required for neutralisation of 1 mol of NaOH.

Options:

A) 49 g

B) 98 g

C) 70 g

D) 34.3 g

Show Answer

Answer:

Correct Answer: C

Solution:

$ H _2SO _4+2NaOH\to Na _2SO _4+2H _2O $

For 1 mole $ NaOH\frac{1}{2} $ mole $ H _2SO _4 $ required Molar mass of $ H _2SO _4 $ =98 g 70 g $ H _2SO _4 $ in 100 g solution

$ \frac{98}{2} $ g $ H _2SO _4 $ in = $ \frac{100}{70}\times 49=70 $ g solution.



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