Some Basic Concepts Of Chemistry Question 6
Question: The mass of 70% $ H _2SO _4 $ required for neutralisation of 1 mol of NaOH.
Options:
A) 49 g
B) 98 g
C) 70 g
D) 34.3 g
Show Answer
Answer:
Correct Answer: C
Solution:
$ H _2SO _4+2NaOH\to Na _2SO _4+2H _2O $
For 1 mole $ NaOH\frac{1}{2} $ mole $ H _2SO _4 $ required Molar mass of $ H _2SO _4 $ =98 g 70 g $ H _2SO _4 $ in 100 g solution
$ \frac{98}{2} $ g $ H _2SO _4 $ in = $ \frac{100}{70}\times 49=70 $ g solution.
