Some Basic Concepts Of Chemistry Question 48
Question: The impure 6 g of NaCl is dissolved in water and then treated with excess of silver nitrate solution. The mass of precipitate of silver chloride is found to be 14 g. The % purity of NaCl solution would be:
Options:
A) 95%
B) 85%
C) 75%
D) 65%
Show Answer
Answer:
Correct Answer: A
Solution:
[a] The reaction that takes place is $ NaCl+AgNO _3\xrightarrow{{}}AgCl\downarrow +NaNO _3 $
$ \therefore $ 143.5 g of $ AgCl $ is produced from 58.5 g
$ \therefore $ 14 g of $ AgCl $ will be produced from $ \frac{58.5\times 14}{143.5}=5.70g,NaCl $ This is the amount of NaCl in common salt; % purity $ =\frac{570}{6}\times 100=95% $ %
