Some Basic Concepts Of Chemistry Question 38

Question: Arrange the following in the order of increasing mass (atomic mass: O=16,Cu=63,N=14 )

I. one atom of oxygen II. one atom of nitrogen III. 1×1010 mole of oxygen IV. 1×1010 mole of copper

Options:

A) II<I<III<IV

B) I<II<III<IV

C) III<II<IV<I

D) IV<II<III<I

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Mass of  6.023×1023 atoms of oxygen = 16 g Mass of one atom of oxygen =166.023×1023=2.66×1023g

Mass of 6.023×1023 atoms of nitrogen =14g Mass of one atom of nitrogen =146.023×1023=2.32×1023g

Mass of 1 mole of oxygen = 16 g Mass of 1×1010 mole of oxygen =16×1010

Mass of 1 mole of copper = 63 g Mass of 1×1010 mole of copper =63×1×1010 =63×1010

So, the order of increasing mass is II < I < III < IV.



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