Some Basic Concepts Of Chemistry Question 38
Question: Arrange the following in the order of increasing mass (atomic mass: $ O=16,Cu=63,N=14 $ )
I. one atom of oxygen II. one atom of nitrogen III. $ 1\times {10^{-10}} $ mole of oxygen IV. $ 1\times {10^{-10}} $ mole of copper
Options:
A) II<I<III<IV
B) I<II<III<IV
C) III<II<IV<I
D) IV<II<III<I
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Mass of $ ~6.023\times 10^{23} $ atoms of oxygen = 16 g Mass of one atom of oxygen $ =\frac{16}{6.023\times 10^{23}}=2.66\times {10^{-23}}g $
Mass of $ 6.023\times 10^{23} $ atoms of nitrogen =14g Mass of one atom of nitrogen $ =\frac{14}{6.023\times 10^{23}}=2.32\times {10^{-23}}g $
Mass of 1 mole of oxygen = 16 g Mass of $ 1\times {10^{-10}} $ mole of oxygen $ =16\times {10^{-10}} $
Mass of 1 mole of copper = 63 g Mass of $ 1\times {10^{-10}} $ mole of copper $ =63\times 1\times {10^{-10}} $ $ =63\times {10^{-10}} $
So, the order of increasing mass is II < I < III < IV.
