Some Basic Concepts Of Chemistry Question 314

Question: The total number of protons in 10 g of calcium carbonate is ( $ N _0=6.023\times 10^{23} $ )

Options:

A) $ 1.5057\times 10^{24} $

B) $ 2.0478\times 10^{24} $

C) $ 3.0115\times 10^{24} $

D) $ 4.0956\times 10^{24} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \because $ 100gm $ CaCO _3\ =6.023\times 10^{23} $ molecules
$ \therefore $ 10gm $ CaCO _3 $ = $ \frac{6.023\times 10^{23}}{100}\times 10 $

$ =6.023\times 10^{22} $ molecule 1 molecule of $ CaCO _3 $ = 50 protons $ 6.023\times 10^{22} $ molecule of $ CaCO _3 $ $ =50\times 6.023\times 10^{22} $

$ =3.0115\times 10^{24} $



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