Some Basic Concepts Of Chemistry Question 314
Question: The total number of protons in 10 g of calcium carbonate is ( $ N _0=6.023\times 10^{23} $ )
Options:
A) $ 1.5057\times 10^{24} $
B) $ 2.0478\times 10^{24} $
C) $ 3.0115\times 10^{24} $
D) $ 4.0956\times 10^{24} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \because $ 100gm $ CaCO _3\ =6.023\times 10^{23} $ molecules
$ \therefore $ 10gm $ CaCO _3 $ = $ \frac{6.023\times 10^{23}}{100}\times 10 $
$ =6.023\times 10^{22} $ molecule 1 molecule of $ CaCO _3 $ = 50 protons $ 6.023\times 10^{22} $ molecule of $ CaCO _3 $ $ =50\times 6.023\times 10^{22} $
$ =3.0115\times 10^{24} $
