Some Basic Concepts Of Chemistry Question 313

Question: 19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered (Au =197) [Pb. CET 1985]

Options:

A) 100

B) $ 6.02\times 10^{23} $

C) $ 6.02\times 10^{24} $

D) $ 6.02\times 10^{25} $

Show Answer

Answer:

Correct Answer: D

Solution:

Amount of gold $ =19.7kg $ $ =19.7\times 1000gm $ =19700gm No. of moles $ =\frac{19700}{197}=100 $

$ \therefore $ No. of atoms $ =100\times 6.023\times 10^{23} $

$ =6.023\times 10^{25} $ atoms.



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