Some Basic Concepts Of Chemistry Question 313
Question: 19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered (Au =197) [Pb. CET 1985]
Options:
A) 100
B) $ 6.02\times 10^{23} $
C) $ 6.02\times 10^{24} $
D) $ 6.02\times 10^{25} $
Show Answer
Answer:
Correct Answer: D
Solution:
Amount of gold $ =19.7kg $ $ =19.7\times 1000gm $ =19700gm No. of moles $ =\frac{19700}{197}=100 $
$ \therefore $ No. of atoms $ =100\times 6.023\times 10^{23} $
$ =6.023\times 10^{25} $ atoms.
