Some Basic Concepts Of Chemistry Question 306

Question: Number of gm of oxygen in 32.2 g $ Na _2SO _4.10H _2O $ is [Haryana PMT 2000]

Options:

A) 20.8

B) 22.4

C) 2.24

D) 2.08

Show Answer

Answer:

Correct Answer: B

Solution:

$ Na _2SO _4\ .\ 10H _2O $ $ =2\times 23+32+4\times 16+10\times 18 $

$ =46+32+64+180=322gm $

322gm $ Na _2SO _4.10H _2O $ contains = 224 gm oxygen 32.2gm $ Na _2SO _4.10H _2O $ contains = $ \frac{32.2\times 224}{322}=22.4,gm $



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