Some Basic Concepts Of Chemistry Question 306
Question: Number of gm of oxygen in 32.2 g $ Na _2SO _4.10H _2O $ is [Haryana PMT 2000]
Options:
A) 20.8
B) 22.4
C) 2.24
D) 2.08
Show Answer
Answer:
Correct Answer: B
Solution:
$ Na _2SO _4\ .\ 10H _2O $ $ =2\times 23+32+4\times 16+10\times 18 $
$ =46+32+64+180=322gm $
322gm $ Na _2SO _4.10H _2O $ contains = 224 gm oxygen 32.2gm $ Na _2SO _4.10H _2O $ contains = $ \frac{32.2\times 224}{322}=22.4,gm $
