Some Basic Concepts Of Chemistry Question 30

Question: A mixture of $ O _2 $ and gas “Y” mol. mass 80 in the mole ratio a : b has a mean molecular mass 40. What would be mean molecular mass, if the gases are mixed in the ratio b : a under, identical conditions? (Assume that gases are non-reacting):

Options:

A) 40

B) 48

C) 62

D) 72

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Let mole fraction of $ O _2 $ is $ x $ $ 40=32\times x+80( 1-x ) $ or $ x=5/6 $ $ a:b=x:( 1-x )=\frac{5}{6}:\frac{1}{6} $ When ratio is changed $ M _{mixture}=32\times \frac{1}{60}+80\times \frac{5}{6}=72 $



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