SATHEE: Some Basic Concepts Of Chemistry Question 30

Some Basic Concepts Of Chemistry Question 30

Question: A mixture of $O_{2}$ and gas “Y” mol. mass 80 in the mole ratio a : b has a mean molecular mass 40. What would be mean molecular mass, if the gases are mixed in the ratio b : a under, identical conditions? (Assume that gases are non-reacting):

Options:

A) 40

B) 48

C) 62

D) 72

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Let mole fraction of $O_{2}$ is $x$ $40 = 32 \times x + 80 (1 - x)$ or $x = 5 / 6$ $a : b = x : (1 - x) = \frac{5}{6} : \frac{1}{6}$ When ratio is changed $M_{m i x t u r e} = 32 \times \frac{1}{60} + 80 \times \frac{5}{6} = 72$

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Some Basic Concepts Of Chemistry Question 30

Question: A mixture of O2 and gas “Y” mol. mass 80 in the mole ratio a : b has a mean molecular mass 40. What would be mean molecular mass, if the gases are mixed in the ratio b : a under, identical conditions? (Assume that gases are non-reacting):

Options:

Answer:

Solution:

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Question: A mixture of $O_{2}$ and gas “Y” mol. mass 80 in the mole ratio a : b has a mean molecular mass 40. What would be mean molecular mass, if the gases are mixed in the ratio b : a under, identical conditions? (Assume that gases are non-reacting):