Some Basic Concepts Of Chemistry Question 278

Question: One litre hard water contains 12.00 mg $ M{g^{2+}} $ milli equivalent of washing soda required to remove its hardness is [CBSE PMT 2001]

Options:

A) 1

B) 12.15

C) $ 1\times {10^{-3}} $

D) $ 12.15\times {10^{-3}} $

Show Answer

Answer:

Correct Answer: A

Solution:

Meq of $ M{g^{+2}}\equiv $ Meq of washing soda $ \frac{W}{E}\times 1000= $ $ M{g^{+2}} $ ; $ EW=\frac{24}{2}=12 $

$ \frac{12\times {10^{-3}}}{12}\times 1000=1 $ .



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