Some Basic Concepts Of Chemistry Question 278
Question: One litre hard water contains 12.00 mg $ M{g^{2+}} $ milli equivalent of washing soda required to remove its hardness is [CBSE PMT 2001]
Options:
A) 1
B) 12.15
C) $ 1\times {10^{-3}} $
D) $ 12.15\times {10^{-3}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Meq of $ M{g^{+2}}\equiv $ Meq of washing soda $ \frac{W}{E}\times 1000= $ $ M{g^{+2}} $ ; $ EW=\frac{24}{2}=12 $
$ \frac{12\times {10^{-3}}}{12}\times 1000=1 $ .
