SATHEE: Some Basic Concepts Of Chemistry Question 251

Some Basic Concepts Of Chemistry Question 251

Question: The ratio of amounts of $H_{2} S$ needed to precipitate all the metal ions from 100 ml of 1 M $A g N O_{3}$ and 100 ml of 1 M $C u S O_{4}$ will be

Options:

A) 1:1

B) 1:2

C) 2:1

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

$A g N O_{3} \equiv 2 A g^{+} + \underset{(H_{2} S)}{S^{2 -}}, \to A g_{2} S$

$∵$ 2 mole $\to$ 1 mole [100×1 =100 millimole]
$∴$ 100 miliimole $\to$ 50 millimole $H_{2} S$ required $C u S O_{4} \equiv C u^{+ 2} + \underset{(H_{2} S)}{S^{2 -}}, \to C u S$

$∵$ 1 mole $\to$ 1 mole [100×1=100 millimole]
$∴$ 100 millimole $\to$ 100 millimole $H_{2} S$ required Ratio $\frac{50}{100} = \frac{1}{2}$ .

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Some Basic Concepts Of Chemistry Question 251

Question: The ratio of amounts of H2S needed to precipitate all the metal ions from 100 ml of 1 M AgNO3 and 100 ml of 1 M CuSO4 will be

Options:

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Question: The ratio of amounts of $H_{2} S$ needed to precipitate all the metal ions from 100 ml of 1 M $A g N O_{3}$ and 100 ml of 1 M $C u S O_{4}$ will be