Some Basic Concepts Of Chemistry Question 251
Question: The ratio of amounts of $ H _2S $ needed to precipitate all the metal ions from 100 ml of 1 M $ AgNO _3 $ and 100 ml of 1 M $ CuSO _4 $ will be
Options:
A) 1:1
B) 1:2
C) 2:1
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ AgNO _3\equiv 2A{g^{+}}+\underset{(H _2S)}{\mathop{{S^{2-}}}},\to Ag _2S $
$ \because $ 2 mole $ \to $ 1 mole [100×1 =100 millimole]
$ \therefore $ 100 miliimole $ \to $ 50 millimole $ H _2S $ required $ CuSO _4\equiv C{u^{+2}}+\underset{(H _2S)}{\mathop{{S^{2-}}}},\to CuS $
$ \because $ 1 mole $ \to $ 1 mole [100×1=100 millimole]
$ \therefore $ 100 millimole $ \to $ 100 millimole $ H _2S $ required Ratio $ \frac{50}{100}=\frac{1}{2} $ .
