Some Basic Concepts Of Chemistry Question 247

Question: The mass of $ BaCO _3 $ produced when excess $ CO _2 $ is bubbled through a solution of 0.205 mol $ Ba{{(OH)}_2} $ is [UPSEAT 2004]

Options:

A) 81 g

B) 40.5 g

C) 20.25 g

D) 162 g

Show Answer

Answer:

Correct Answer: B

Solution:

$ Ba{{(OH)}_2}+CO _2\to BaCO _3+H _2O $

Atomic wt. of $ BaCO _3 $ = $ 137+12+16\times 3 $ = 197 No. of mole $ =\frac{wt\text{. of substance}}{\text{mol wt}\text{.}} $

$ \because $ 1 mole of $ Ba{{(OH)}_2} $ gives 1 mole of $ BaCO _3 $

$ \therefore $ 205 mole of $ Ba{{(OH)}_2} $ will give .205 mole of $ BaCO _3 $

$ \therefore $ wt. of 0.205 mole of $ BaCO _3 $ will be $ .205\times 197=40.385gm\approx ,40.5,gm $



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