Some Basic Concepts Of Chemistry Question 247
Question: The mass of $ BaCO _3 $ produced when excess $ CO _2 $ is bubbled through a solution of 0.205 mol $ Ba{{(OH)}_2} $ is [UPSEAT 2004]
Options:
A) 81 g
B) 40.5 g
C) 20.25 g
D) 162 g
Show Answer
Answer:
Correct Answer: B
Solution:
$ Ba{{(OH)}_2}+CO _2\to BaCO _3+H _2O $
Atomic wt. of $ BaCO _3 $ = $ 137+12+16\times 3 $ = 197 No. of mole $ =\frac{wt\text{. of substance}}{\text{mol wt}\text{.}} $
$ \because $ 1 mole of $ Ba{{(OH)}_2} $ gives 1 mole of $ BaCO _3 $
$ \therefore $ 205 mole of $ Ba{{(OH)}_2} $ will give .205 mole of $ BaCO _3 $
$ \therefore $ wt. of 0.205 mole of $ BaCO _3 $ will be $ .205\times 197=40.385gm\approx ,40.5,gm $
