Some Basic Concepts Of Chemistry Question 169

Question: The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be [Bihar CET 1995]

Options:

A) 11.2 L

B) 22.4 L

C) 1 L

D) 44.8 L

Show Answer

Answer:

Correct Answer: A

Solution:

Molecular weight $ =2\times V.D $ $ =2\times 11.2=22.4 $

$ \because $ 22.4gm of gas occupies 22.4L at S.T.P.
$ \therefore $ 11.2gm of gas occupies $ \frac{22.4}{22.4}\times 11.2=11.2L $ .



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