Some Basic Concepts Of Chemistry Question 169
Question: The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be [Bihar CET 1995]
Options:
A) 11.2 L
B) 22.4 L
C) 1 L
D) 44.8 L
Show Answer
Answer:
Correct Answer: A
Solution:
Molecular weight $ =2\times V.D $ $ =2\times 11.2=22.4 $
$ \because $ 22.4gm of gas occupies 22.4L at S.T.P.
$ \therefore $ 11.2gm of gas occupies $ \frac{22.4}{22.4}\times 11.2=11.2L $ .
