Some Basic Concepts Of Chemistry Question 161

Question: In the reaction $ 2Na _2S _2O _3+I _2\to Na _2S _4O _6+2NaI $ , the equivalent weight of $ Na _2S _2O _3 $ (mol. wt. = M) is equal to

Options:

A) M

B) $ M/2 $

C) $ M/3 $

D) $ M/4 $

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Answer:

Correct Answer: A

Solution:

$ \overset{+2}{\mathop{Na _2SO _3}},+I _2\to \overset{+2.5}{\mathop{Na _2S _4O _6}},+NaI $

$ n=2\times 0.5=1 $

$ E=\frac{M}{n-factor}=\frac{M}{1}=M $



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