Some Basic Concepts Of Chemistry Question 161
Question: In the reaction $ 2Na _2S _2O _3+I _2\to Na _2S _4O _6+2NaI $ , the equivalent weight of $ Na _2S _2O _3 $ (mol. wt. = M) is equal to
Options:
A) M
B) $ M/2 $
C) $ M/3 $
D) $ M/4 $
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Answer:
Correct Answer: A
Solution:
$ \overset{+2}{\mathop{Na _2SO _3}},+I _2\to \overset{+2.5}{\mathop{Na _2S _4O _6}},+NaI $
$ n=2\times 0.5=1 $
$ E=\frac{M}{n-factor}=\frac{M}{1}=M $
