Some Basic Concepts Of Chemistry Question 130
Question: Arrange the following (I to IV) in the order of increasing masses.
I. 0.5 mole of $ O _3 $ II. $ 3.01\times 10^{23} $ molecules of $ O _2 $ III. 5.6 L of $ CO _2 $ at STP IV. 0.5 g atom of $ O _2 $
Options:
A) IV < III < II < I
B) II < I < III < IV
C) II = I < III < IV
D) I < III < IV < II
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Idea: To solve this problem student is ad vised to keep in mind the clear understanding of mole concept. $ \text{Number of moles}=\frac{Wt.\text{ in gram}}{\text{Molecular mass}} $
(I) 0.5 mol of $ O _3=24gO _3 $
(II) $ 3.01\times 10^{23} $ molecules of $ O _2=16gO _2 $
(III) 5.6L of $ CO _2=\frac{5.6}{22.4}\times 44=11gCO _2 $
(IV) 0.5 g atom of $ O _2=8g $
Hence, IV < III < II < I
