Some Basic Concepts Of Chemistry Question 130

Question: Arrange the following (I to IV) in the order of increasing masses.

I. 0.5 mole of $ O _3 $ II. $ 3.01\times 10^{23} $ molecules of $ O _2 $ III. 5.6 L of $ CO _2 $ at STP IV. 0.5 g atom of $ O _2 $

Options:

A) IV < III < II < I

B) II < I < III < IV

C) II = I < III < IV

D) I < III < IV < II

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Idea: To solve this problem student is ad vised to keep in mind the clear understanding of mole concept. $ \text{Number of moles}=\frac{Wt.\text{ in gram}}{\text{Molecular mass}} $

(I) 0.5 mol of $ O _3=24gO _3 $

(II) $ 3.01\times 10^{23} $ molecules of $ O _2=16gO _2 $

(III) 5.6L of $ CO _2=\frac{5.6}{22.4}\times 44=11gCO _2 $

(IV) 0.5 g atom of $ O _2=8g $

Hence, IV < III < II < I



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