Solutions Question 56
Question: A 0.001 molal solution of $ [Pt{{(NH_3)}4}Cl_4] $ in water had a freezing point depression of $ {{0.0054}^{o}}C $ . If $ K{f} $ for water is 1.80, the correct formulation for the above molecule is [Kerala CET (Med.) 2003]
Options:
A) $ [Pt{{(NH_3)}_4}Cl_3],Cl $
B) $ [Pt{{(NH_3)}_4}Cl],Cl_2 $
C) $ [Pt{{(NH_3)}_4}Cl_2],Cl_3 $
D) $ [Pt{{(NH_3)}_4}Cl_4] $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta T_{f}=imk_{f} $ ; $ 0.0054=i\times 1.8\times 0.001 $
$ i=3 $ so it is $ [Pt{{(NH_3)}_4}Cl]Cl_2 $ .
