Solutions Question 406

Question: Match List I with List II and select the correct answer using the code given below the lists:
List (I) List (II)
[A] 50 mL of 3M HCl solution +150 mL of 1 M $ FeCl_3 $ solution (p) 4.17 m
[B] An aqueous solution of NaCl with mole fraction of NaCl as 0.1 (q) $ [C{l^{-}}]=3M $
[C] 20% (w/w) propanol $ (C_3H_7OH) $ solution (r) $ [{H^{+}}]=2.75M $
[D] 10.95% (w/v) HCl solution (s) 6.1 m

Options:

A) A-r, B-s, C-p, D-q

B) A-q, B-s, C-r, D-q

C) A-q, B-s, C-p, D-q

D) A-q, B-r, C-p, D-s

Show Answer

Answer:

Correct Answer: C

Solution:

[a] $ [C{l^{-}}]=\frac{50\times 3+150\times 1\times 3}{200}=\frac{600}{200}=3M $ [b] Molality $ =\frac{0.1}{0.9\times 18}\times 1000=6.17,m $ [c] Molality $ =\frac{10\times 1000}{60\times 90}=1.85,m $ [d] Molarity of $ HCl=\frac{\frac{10.95}{36.5}}{100}\times 1000=3M $



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