Solutions Question 406
Question: Match List I with List II and select the correct answer using the code given below the lists:
| List (I) | List (II) |
|---|---|
| [A] 50 mL of 3M HCl solution +150 mL of 1 M $ FeCl_3 $ solution | (p) 4.17 m |
| [B] An aqueous solution of NaCl with mole fraction of NaCl as 0.1 | (q) $ [C{l^{-}}]=3M $ |
| [C] 20% (w/w) propanol $ (C_3H_7OH) $ solution | (r) $ [{H^{+}}]=2.75M $ |
| [D] 10.95% (w/v) HCl solution | (s) 6.1 m |
Options:
A) A-r, B-s, C-p, D-q
B) A-q, B-s, C-r, D-q
C) A-q, B-s, C-p, D-q
D) A-q, B-r, C-p, D-s
Show Answer
Answer:
Correct Answer: C
Solution:
[a] $ [C{l^{-}}]=\frac{50\times 3+150\times 1\times 3}{200}=\frac{600}{200}=3M $ [b] Molality $ =\frac{0.1}{0.9\times 18}\times 1000=6.17,m $ [c] Molality $ =\frac{10\times 1000}{60\times 90}=1.85,m $ [d] Molarity of $ HCl=\frac{\frac{10.95}{36.5}}{100}\times 1000=3M $
