SATHEE: Solutions Question 405

Solutions Question 405

Question: Suppose 5 gm of $C H_{3} C O O H$ is dissolved in one litre of ethanol. Assume that no reaction between them takes place. Calculate molality of resulting solution if density of ethanol is 0.789 gm/ml.

Options:

A) 0.0856

B) 0.0956

C) 0.1056

D) 0.1156

Show Answer

Answer:

Correct Answer: C

Solution:

Weight of $C H_{3} C O O H$ dissolved = 5 g Eq. of $C H_{3} C O O H$ dissolved $= \frac{5}{60}$ Volume of ethanol = 1 litre = 1000 ml.

$∴$ Weight of ethanol =1000 $\times$ 0.789 = 789 g

$∴$ Molality of solution $= \frac{M o l e s, o f, s o l u t e}{W e i g h t, o f, s o l v e n t, i n}$ $= \frac{\frac{5}{60 \times 789}}{1000} = 0.1056$

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Solutions Question 405

Question: Suppose 5 gm of CH3COOH is dissolved in one litre of ethanol. Assume that no reaction between them takes place. Calculate molality of resulting solution if density of ethanol is 0.789 gm/ml.

Options:

Answer:

Solution:

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Question: Suppose 5 gm of $C H_{3} C O O H$ is dissolved in one litre of ethanol. Assume that no reaction between them takes place. Calculate molality of resulting solution if density of ethanol is 0.789 gm/ml.