Solutions Question 405

Question: Suppose 5 gm of $ CH_3COOH $ is dissolved in one litre of ethanol. Assume that no reaction between them takes place. Calculate molality of resulting solution if density of ethanol is 0.789 gm/ml.

Options:

A) 0.0856

B) 0.0956

C) 0.1056

D) 0.1156

Show Answer

Answer:

Correct Answer: C

Solution:

Weight of $ CH_3COOH $ dissolved = 5 g Eq. of $ CH_3COOH $ dissolved $ =\frac{5}{60} $ Volume of ethanol = 1 litre = 1000 ml.

$ \therefore $ Weight of ethanol =1000 $ \times $ 0.789 = 789 g

$ \therefore $ Molality of solution $ =\frac{Moles,of,solute}{Weight,of,solvent,in} $ $ =\frac{\frac{5}{60\times 789}}{1000}=0.1056 $



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