Solutions Question 314
Question: Lowering of vapour pressure of 1.00 m solution of a non-volatile solute in a hypothetical solvent of molar mass 40 g at its normal boiling point, is:
Options:
A) 29.23 torr
B) 30.4 torr
C) 35.00 torr
D) 40.00 torr
Show Answer
Answer:
Correct Answer: A
Solution:
$ P_solvent^{{}^\circ }=760,torr $ (at the b. pt); $ n_{solute}=1 $
$ n_{solvent}=\frac{1000}{40}=25; $
$ \Delta P=760\times X_{solute}=\frac{760}{26},torr=29.23,torr $
