Solutions Question 314

Question: Lowering of vapour pressure of 1.00 m solution of a non-volatile solute in a hypothetical solvent of molar mass 40 g at its normal boiling point, is:

Options:

A) 29.23 torr

B) 30.4 torr

C) 35.00 torr

D) 40.00 torr

Show Answer

Answer:

Correct Answer: A

Solution:

$ P_solvent^{{}^\circ }=760,torr $ (at the b. pt); $ n_{solute}=1 $

$ n_{solvent}=\frac{1000}{40}=25; $

$ \Delta P=760\times X_{solute}=\frac{760}{26},torr=29.23,torr $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक