Solutions Question 313

Question: The vapour pressure (at the standard boiling point of water) of an aqueous solution containing 28% by mass of a non-volatile normal solute (molecular mass = 28) will be

Options:

A) 152 torr

B) 608 torr

C) 760 torr

D) 547 torr

Show Answer

Answer:

Correct Answer: B

Solution:

Moles of solute $ =\frac{28}{28}=1; $ moles of water $ =\frac{100-28}{18}=4 $ V.P. of solution

$ =P _{H_2O}^{{}^\circ }\times {X _{H_2O}}=760\times \frac{4}{5}=608,torr $



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