Solutions Question 313
Question: The vapour pressure (at the standard boiling point of water) of an aqueous solution containing 28% by mass of a non-volatile normal solute (molecular mass = 28) will be
Options:
A) 152 torr
B) 608 torr
C) 760 torr
D) 547 torr
Show Answer
Answer:
Correct Answer: B
Solution:
Moles of solute $ =\frac{28}{28}=1; $ moles of water $ =\frac{100-28}{18}=4 $ V.P. of solution
$ =P _{H_2O}^{{}^\circ }\times {X _{H_2O}}=760\times \frac{4}{5}=608,torr $
