Solutions Question 290
Question: The osmotic pressure in atmospheres of 10% solution of canesugar at $ 69^{o}C $ is [AFMC 1991]
Options:
A) 724
B) 824
C) 8.21
D) 7.21
Show Answer
Answer:
Correct Answer: C
Solution:
$ \pi V=nRT $
$ \pi =\frac{w}{m}\frac{RT}{V}=\frac{10}{342}\times \frac{0.821\times (273+69)}{0.1} $ = 8.21 atm.
