Solutions Question 290

Question: The osmotic pressure in atmospheres of 10% solution of canesugar at $ 69^{o}C $ is [AFMC 1991]

Options:

A) 724

B) 824

C) 8.21

D) 7.21

Show Answer

Answer:

Correct Answer: C

Solution:

$ \pi V=nRT $

$ \pi =\frac{w}{m}\frac{RT}{V}=\frac{10}{342}\times \frac{0.821\times (273+69)}{0.1} $ = 8.21 atm.



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