SATHEE: Solutions Question 275

Solutions Question 275

Question: A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance $X$ . The molecular weight of $X$ is [CBSE PMT 1998]

Options:

A) 34.2

B) 171.2

C) 68.4

D) 136.8

Show Answer

Answer:

Correct Answer: C

Solution:

Molar concentration of cane sugar $= \frac{5}{342} \times \frac{1000}{100} = \frac{50}{342}$ Molar concentration of X = $\frac{1}{m} \times \frac{1000}{100} = \frac{10}{m}$

$\frac{10}{m} = \frac{50}{342}$ or $m = 68.4$ .

Solutions Question 275

Question: A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance $X$ . The molecular weight of $X$ is [CBSE PMT 1998]

Options:

Answer:

Solution:

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Solutions Question 275

Question: A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance X . The molecular weight of X is [CBSE PMT 1998]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance $X$ . The molecular weight of $X$ is [CBSE PMT 1998]