Solutions Question 275

Question: A 5% solution of canesugar (mol. wt. =342) is isotonic with 1% solution of a substance $ X $ . The molecular weight of $ X $ is [CBSE PMT 1998]

Options:

A) 34.2

B) 171.2

C) 68.4

D) 136.8

Show Answer

Answer:

Correct Answer: C

Solution:

Molar concentration of cane sugar $ =\frac{5}{342}\times \frac{1000}{100}=\frac{50}{342} $ Molar concentration of X = $ \frac{1}{m}\times \frac{1000}{100}=\frac{10}{m} $

$ \frac{10}{m}=\frac{50}{342} $ or $ m=68.4 $ .



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