Solutions Question 266

Question: If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at $ 15^{o}C $ . Then the osmotic pressure of this solution will be [MP PMT 1986]

Options:

A) 0.34 atm

B) 0.65 atm

C) 6.57 atm

D) 5.57 atm

Show Answer

Answer:

Correct Answer: C

Solution:

$ \pi =CRT=\frac{3\times 1000}{180\times 60}\times 0.0821\times 288 $

$ =6.56,atm $ .



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