Solutions Question 266
Question: If 3 gm of glucose (mol. wt. 180) is dissolved in 60 gm of water at $ 15^{o}C $ . Then the osmotic pressure of this solution will be [MP PMT 1986]
Options:
A) 0.34 atm
B) 0.65 atm
C) 6.57 atm
D) 5.57 atm
Show Answer
Answer:
Correct Answer: C
Solution:
$ \pi =CRT=\frac{3\times 1000}{180\times 60}\times 0.0821\times 288 $
$ =6.56,atm $ .
