SATHEE: Solutions Question 242

Solutions Question 242

Question: If 18 gm of glucose $(C_{6} H_{12} O_{6})$ is present in 1000 gm of an aqueous solution of glucose, it is said to be [CPMT 1986]

Options:

A) 1 molal

B) 1.1 molal

C) 0.5 molal

D) 0.1 molal

Show Answer

Answer:

Correct Answer: D

Solution:

$\frac{18}{180 \times 1} = \frac{1}{10} = 0.1,$ molal.

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Solutions Question 242

Question: If 18 gm of glucose (C6H12O6) is present in 1000 gm of an aqueous solution of glucose, it is said to be [CPMT 1986]

Options:

Answer:

Solution:

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Question: If 18 gm of glucose $(C_{6} H_{12} O_{6})$ is present in 1000 gm of an aqueous solution of glucose, it is said to be [CPMT 1986]