Solutions Question 242
Question: If 18 gm of glucose $ (C_6H_{12}O_6) $ is present in 1000 gm of an aqueous solution of glucose, it is said to be [CPMT 1986]
Options:
A) 1 molal
B) 1.1 molal
C) 0.5 molal
D) 0.1 molal
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{18}{180\times 1}=\frac{1}{10}=0.1, $ molal.
