Solutions Question 236

Question: If we take $ 44g $ of $ CO_2 $ and $ 14g $ of $ N_2 $ what will be mole fraction of $ CO_2 $ in the mixture [KCET 1990]

Options:

A) 1/5

B) 1/3

C) 2/3

D) ¼

Show Answer

Answer:

Correct Answer: C

Solution:

Mole fraction of CO2 $ =\frac{{n_{CO_2}}}{{n_{CO_2}}+{n_{N_2}}} $

$ =,\frac{\frac{44}{44}}{\frac{44}{44}+\frac{14}{28}}=\frac{2}{3} $ .



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