Solutions Question 236
Question: If we take $ 44g $ of $ CO_2 $ and $ 14g $ of $ N_2 $ what will be mole fraction of $ CO_2 $ in the mixture [KCET 1990]
Options:
A) 1/5
B) 1/3
C) 2/3
D) ¼
Show Answer
Answer:
Correct Answer: C
Solution:
Mole fraction of CO2 $ =\frac{{n_{CO_2}}}{{n_{CO_2}}+{n_{N_2}}} $
$ =,\frac{\frac{44}{44}}{\frac{44}{44}+\frac{14}{28}}=\frac{2}{3} $ .
