Solutions Question 222

Question: In a mixture of 1 gm $ H_2 $ and 8 gm $ O_2 $ , the mole fraction of hydrogen is [Orissa JEE 2002]

Options:

A) 0.667

B) 0.5

C) 0.33

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

Mole fraction $ =\frac{n}{n+N}=\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}} $

$ =\frac{\frac{1}{2}}{\frac{1}{2}+\frac{8}{32}}=0.667 $ .



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