Solutions Question 222
Question: In a mixture of 1 gm $ H_2 $ and 8 gm $ O_2 $ , the mole fraction of hydrogen is [Orissa JEE 2002]
Options:
A) 0.667
B) 0.5
C) 0.33
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Mole fraction $ =\frac{n}{n+N}=\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}} $
$ =\frac{\frac{1}{2}}{\frac{1}{2}+\frac{8}{32}}=0.667 $ .
