SATHEE: Solutions Question 212

Solutions Question 212

Question: When $6 g m$ urea dissolve in $180, g m, H_{2} O$ . The mole fraction of urea is [CPMT 1988]

Options:

A) $\frac{10}{10.1}$

B) $\frac{10.1}{10}$

C) $\frac{10.1}{0.1}$

D) $\frac{0.1}{10.1}$

Show Answer

Answer:

Correct Answer: D

Solution:

Mole fraction $X = \frac{n}{n + N}$

$= \frac{\frac{6}{60}}{\frac{6}{60} + \frac{180}{18}} = \frac{0.1}{10.1}$ .

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Solutions Question 212

Question: When 6gm urea dissolve in 180,gm,H2O . The mole fraction of urea is [CPMT 1988]

Options:

Answer:

Solution:

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Question: When $6 g m$ urea dissolve in $180, g m, H_{2} O$ . The mole fraction of urea is [CPMT 1988]